Chemistry, asked by karthickak, 9 months ago

in diamond carbon atoms occupy FCC lattice points as well as alternate tetrahedral voids. if edge length of the unit cell is 3.56 pm then the radius of the carbon atom is

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Answered by thakurchanchal169

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In diamond, carbon atom occupy FCC lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is 356 pm, then the radius of carbon atom is : A

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in diamond carbon atoms occupy FCC lattice points as well as alternate tetrahedral voids. if edge length of the unit cell is 3.56 pm then the radius of the carbon atom is​

Answers

in diamond carbon atoms occupy FCC lattice points as well as alternate tetrahedral voids. if edge length of the unit cell is 3.56 pm then the radius of the carbon atom is