In differential axle and wheel diameter of wheel is 40cm and that of axles are 10cm and 8cm. If an effort of 50N lifts a load of 1500N. Find efficiency of machine.
75%
70%
65%
60%
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Given : In differential axle and wheel diameter of wheel is 40cm and that of axles are 10cm and 8cm. If an effort of 50N lifts a load of 1500N.
To Find : efficiency of machine.
75%
70%
65%
60%
Solution:
Velocity Ratio in differential axle = 2 * Dia wheel / ( difference in axle dia)
= 2 * 40 / ( 10 - 8)
= 40
an effort of 50N lifts a load of 1500N
Equivalent Effort = Effort * Velocity Ratio
=> Equivalent Effort = 40 * 50 = 2000N
2000 N Equivalent Effort lifts a load of 1500N
=> efficiency of machine. = (1500/2000) * 100
= 75 %
efficiency of machine. is 75 %
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