Question

In diffraction using single slit, a slit of width a is illuminated by white light. For red light (a = 6500 A), the first
minima is obtained for 0 = 30°. Then the value of a will be
(1) 3250 A
(2) 6.5 x 104
(3) 1.30 um
(4) 2.6 x10^-4

Answer 1

Answer:

There is something wrong with your options. Please Check.

Explanation:

A sin theta = n x Lambda

A sin 30 = 1 x 6500 * 10^-10

A =( 6500 * 10^-10) / 1/2

A = 1.3 x 10^-9

Answer 2

hi mate here is the answer

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The position of n

th

dark fringe in Fraunhoffer Diffraction from a single slit is

asinθ = nλ

a=nh/sin∅

a= 1.30um