Question

in dividing x3- 3x2+5x-7 by x2-2x+4 the remainder is the form ax+b find the value of a and b

Answer 1

pardon me if it is wrong.

Answer 2

The value of a is -1 and the value of b is -3.

Step-by-step explanation:

It is given that the remainder of

$\dfrac{x^3-3x^2+5x-7}{x^2-2x+4}$

is in the form ax+b. We need to find the value of a and b.

Divide the polynomial by long division method as shown below.

Dividend = $x^3-3x^2+5x-7$

Divisor = $x^2-2x+4$

Quotient = $x-1$

Remainder = $-x-3$

Compare the remainder by ax+b.

$ax+b=-x-3$

On comparing both sides we get

$a=-1,b=-3$

Therefore, the value of a is -1 and the value of b is -3.

#Learn more

(x3-4x2+5x-2) by (x2+2x-1)​

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