Question

in division fact p(x)=g(x) q(x) +r(x) .if g(x) = q(x) and r(x)=0 . show that p(x) is a perfect square.
​

Answer 1

Since,

r(x) = 0p

(x) = q(x) g(x) + 0

p(x) = q(x) q(x) [g(x) = q(x)] p(x) = [q(x)] square

So p(x) is perfect square of q(x)