Question

In double-slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1º. What is the spacing between the two slits?

Answer 1

In double-slit experiment using light of wavelength, λ = 600 nm, the angular width of a fringe formed on a distant screen, $\theta$=0.1º. we have to find the space between two slits.

use the formula,

angular width , $\theta=\frac{\lambda}{d}$

here, d is space between two slits.

so, d = $\frac{\lambda}{\theta}$

here, $\theta$ = 0.1° = 0.1π/180rad [ as we know, 1° = π/180 rad]

= (600nm)/(0.1π/180)

= (600 × 10^-10m)/(0.1π/180)

= (600 × 180 × 10^-10)/(0.1π)

= 3.44 × 10^-4 m or, 0.344mm

hence, the space between slits is 3.44 × 10^-4 m .

also read : Answer the following questions (a) When a low flying aircraft passes overhead, we sometimes notice a slight shaking of t...

https://brainly.in/question/11372408

In deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of nλ/a. Justify thi...

https://brainly.in/question/11372429.