Question

In double slit experiment using light of wavelength
600 nm, if angular fringe width is 0.1° then
separation between two slits is
(1) 0.5 mm
(2) 0.34 mm
(3) 0.72 mm
(4) 0.89 mm

Answer 1

Explanation:

Reference of diagram is given below:-

Given:-

Length(AB/CD) = 4 × breadth

Area of rectangle = 1600 sq.m

To find:-

Diagonal of rectangle (AC/BD) =?

Now, let breadth be x m and length be 4x m.

\begin{lgathered}\rm We \:know, \\\\\dag \: {\boxed{\rm{Area \: of \: rectangle = Length \times Breadth }}}\end{lgathered}

Weknow,

†

Areaofrectangle=Length×Breadth

A/Q,

\begin{lgathered}\dashrightarrow\sf 4x \times x = 1600 \\\\\dashrightarrow\sf 4x^2 = 1600 \\\\\dashrightarrow\sf x^2 = 1600/4 \\\\\dashrightarrow\sf x^2 = 400 \\\\\dashrightarrow\sf x = \sqrt{400} \\\\\dashrightarrow\sf x ={\boxed{\sf\green{20 \: m }}}\end{lgathered}

⇢4x×x=1600

⇢4x

2

=1600

⇢x

2

=1600/4

⇢x

2

=400

⇢x=

400

⇢x=

20m

\dashrightarrow\sf Breadth = x = {\boxed{\sf\green{20\: m }}}⇢Breadth=x=

20m