In Dumas method for estimation of nitrogen, 0.80 g of an organic compound gave 60 ml of nitrogen collected at 300 K and 715 mm pressure. The % composition of nitrogen in the compound (aq. tension at 300 K is 15 mm) O 34.2% O 69.30% O 78.56% O 7.8%
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Given:- aqueous tension= 15mm mass of organic compound= 0.80g 60 ml nitrogen composition.
To find:- The % composition of nitrogen in the compound
Solution:
To obtain the pressure of nitrogen subtract aqueous tension 15mm from 715mm pressure
P = 700 mm of Hg.
Volume of nitrogen at stp is give by:-
= V*P*273/T*760
= 60*700*273/300*760
= 50.29 mL
Now calculate the percent of nitrogen,
= vol of n2 at stp * 28 *100/wt *22400
= 50.29 * 28 *100 / 0.80 *22400
= 7.86%
Therefore the percentage is 7.86%
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