Question

In duration of sometimes the compound interest on ₹1800 at 10% per annum is ₹378. Find the duration of time. Intext:zigya

Answer 1

Hey here is your answer

your question is :-

In duration of sometimes the compound interest on ₹1800 at 10% per annum is ₹378. Find the duration of time ?

your answer is :-

As we know the formula

$a \: = p(1 + \frac{r}{100} {)}^{t}$

Here a = amount

p = principle

r = rate

t = time

let the time be x

amount = principle + compound interest

amount = 1800 rs. + 378 rs.

amount = 2178 rs.

rate = 10 %

principle = 1800 rs.

So, let's start the answer :-

$a \: = p(1 + \frac{r}{100} {)}^{t} \\ \\ 2178 = 1800 \times (1 + \frac{10}{100} {)}^{x} \\ \\ 2178 = 1800 \times (\frac{110}{100} {)}^{x} \\ \\ (\frac{110}{100} {)}^{x} = \frac{2178}{1800} \\ \\ (\frac{11}{10} {)}^{x} = \frac{121}{100} \\ \\ (\frac{11}{10} {)}^{x} = (\frac{11}{10} {)}^{2} \\ \\ x = 2$
So , here x = 2 means the time is 2 years.

Hope this helps you

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Answer 2

hey there➡️

here ur answer which i wrote and attached for u❗

hope this helps u✅✔️✅✔️

be brainly❤️