Math, asked by namaysehgal123, 1 month ago

in dy/dx=d(x^2+y^2) /dx, why d(t^2)/dx =2t.dt/dx​

Answers

Answered by lovyboy
0

Answer:

For parametric form of equation,

d

y

d

x

=

d

y

d

t

d

x

d

t

.

Here as

x

=

t

2

2

t

,

d

x

d

t

=

2

t

2

=

2

(

t

1

)

and as

y

=

t

4

4

t

,

d

y

d

t

=

4

t

3

4

=

4

(

t

3

1

)

=

4

(

t

1

)

(

t

2

+

t

+

1

)

Hence

d

y

d

x

=

4

(

t

1

)

(

t

2

+

t

+

1

)

2

(

t

1

)

=

2

(

t

2

+

t

+

1

)

Answered by abhaysingh27052019
1

Answer:

here is the answer

Step-by-step explanation:

please mark as

Attachments:
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