Question

In each case find the smallest number which when divided by each of the numbers gives the common remainder (1)22,33,121 : remainder 1​

Answer 1

Step-by-step explanation:

Firstly subtract 1 from all the numbers

22-1=21

33-1=32

121-1=120

LCM of (21, 32,120)

21=7*3

32=2^5

120=2^3*3*5

LCM= 2^5*3*7*5= 3360

Hope it helps!