Question

in each case given below find the value of angle A , where 0°<A <90°

(I) sin(90°-3A) •cosec 42° = 1
(ii) cos( 90°-A)•sec77°=1

[answer step by step]​

Answer 1

Step-by-step explanation:

1)Since , sin theta • cosec theta=1

→sin(90-3A)• cosec 42= sin42• cosec42 {since , A is acute angle }

→sin(90-3A)= sin42

→90-3A= 42

→3A =90-42

→A=48/3

→A=16

2) Since , cos theta •sec theta =1

→cos(90-A)• sec 77= cos 77• sec77{since , A is acute angle }

→cos(90-A)= cos 77

→90-A =77

→- A=77-90

→-A=-13

→A=13

Answer 2

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