In each of the figures [(i)-(iv)] given below, a line segment is drawn parallel to one side of the triangle and the lengths of certain line-segment are marked. Find the value of x in each of the following :
(i)
(ii)
(iii)
(iv)
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SOLUTION :
BASIC PROPORTIONALITY THEOREM (BPT) is used in this question .
If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio.
This theorem also known as ‘Thales theorem’.
(i) 1/c =d/x
x×1 = c×d (by cross multiplication)
x = cd
Hence, the value of x is cd .
(ii) a/1 = b/x
a × x = b × 1 (by cross multiplication)
x = b/a
Hence, the value of x is b/a.
(iii) g/x = 1/g
g × g = x × 1 (by cross multiplication)
g² = x
Hence, the value of x is g².
(iv) 1/x = h/1
x × h = 1 (by cross multiplication)
x = 1/h
Hence, the value of x is 1/h .
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i think these may be ur answers
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