In each of the follorcing, determine the value of k for which the given value is the solution of equation.
(1) kx²-3x + 2=0; x = 2
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Answer:
k(2)^2-3(2)+2=0
=4k-6+2=0
=4k-4=0
=4k=4
=k=4÷4
=k=1
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