Math, asked by pnandini071, 11 months ago

In each of the follorcing, determine the value of k for which the given value is the solution of equation.
(1) kx²-3x + 2=0; x = 2​

Answers

Answered by paras4099
2

Answer:

k(2)^2-3(2)+2=0

=4k-6+2=0

=4k-4=0

=4k=4

=k=4÷4

=k=1

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