Question

In each of the following , determine the value of k for which the given value is a solution

Of the equation :

a) kx² + 2x – 3 = 0 , x = 2
(b) 3x² + 2kx - 3 = = , x = -1/2

c) x² + 2ax – k = 0 , x= -a​

Answer 1

Step-by-step explanation:

a part

k(2)² + 2(2) -3 =0

4k +4 -3 =0

4k+1=0

4k=0-1

4k=-1

k = -1/4

b part

3(-1/2)² + 2k(-1/2)-3=0

3(1/4) + (-1)k -3=0

3/4 - k -3=0

3/4-k=0+3

3/4-k=3

-k = 3 - 3/4

- k = 9/4

c part

(-a)² + 2a(-a) -k =0

a² + 2-a² =0+k

a² + 2-a²=k

a² - a² +2=k

0+2=k

2=k