Question

in each of the following, determine the value of p for which the given value is a solution of the equation. px^2+√2x-4=0, x=√2​

Answer 1

Answer:

px^2+√2x-4=0 - (1) where x=√2

sub x=√2 in equation (1)

p(√2)^2+√2*√2-4=0

p(√2*√2)+2-4=0

p*2+2-4=0

2p-2=0

2p=2

p=2/2

p=1