Math, asked by Bhargavikhandagale, 6 hours ago

In each of the following determine whether the given values are solution of the given equation or not: (i) 3x2 - 2x-1=0, x = 1 (ii) 6x2 - x - 2 = 0, x = -1/2, x = 2/3 (ii) x2-x+1 = 0, x = 1, x = -1 (iv) x2 + √2x - 4 = 0, x = √2, x = -2/√2​

Answers

Answered by pritygupta9162900034
0

Step-by-step explanation:

i) 6×2-×-2=0,×=-1/2,×=2/3

I hope the right answer

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