in each of the following figure ab is parallel to CD find the value of x in each case
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- x=140degree
- x=100degree
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Answer:
x=240°
Step-by-step explanation:
= Draw a line EF perpendicular to AB and CD passing through M.
In ∆BME
= angle BME + angle MBE + angle BEM= 180(angle sum property)
angle BME=35°+90°=180°
=angle BME=180°- 125°
=angle BME=45°
In ∆ DMF
angle DMF +angle MDF+ angle MED= 180°( angle sum property)
= angle DMF+75°+90°
= angle DMF= 180°- 165°
= angle DMF= 15°
= x = angle DMF+angle BME + angle EMF
=x= 15°+45°+180°
=x=240°
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