In each of the following figure an altitude
is drawn to the hypotenuse. The length of
different segments are marked in each Figure.
Determine the value of x, y and z in each case
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In a right triangle, the altitude that’s perpendicular to the hypotenuse has a special property: it creates two smaller right triangles that are both similar to the original right triangle.
(i) In △ABC, BD is altitude.
If an altitude is drawn to the hypotenuse of a right triangle as shown in the above figure, then
(AD)2=AD×AC
⇒ (x)2=4×9
⇒ x2=36
∴ x=6
Now, (BC)2=DC×AC
⇒ z2=5×9
⇒ z2=45
∴ z=35
Next, (BD)2=AD×DC
⇒ y2=4×5
⇒ y2=20
∴ y=25
(ii) In △PQR, QS is an altitude.
If an altitude is drawn to the hypotenuse of a right triangle as shown in the above figure, then
(PQ)2=PS×PR
(6)2=4×(4+x)
36=16+4x
4x=20
∴ x=5
∴ SR=5
Now, QR2=SR×
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