In each of the following figure, O is the centre of the circle. Find the measure of each lettered angle.
Answers
Given, in the following figure, O is the centre of the circle, ∠BAC is 63° and ∠BCA is x .
In ∆ABC,
∠BAC = 63°
∠ABC = 90° (Angle in a semi-circle is 90°)
∠BCA = x
By using the angle sum property of a triangle, we get
∠BAC + ∠ABC + ∠BCA = 180°
By putting the respected values, we get
63° + 90° + x = 180°
or, 123° + x = 180°
By transposition method, we get
or, x = 180° - 123°
or, x = 57°
Answer:
The value of x is 57° .
Given, in the following figure, O is the centre of the circle, ∠BAC is 63° and ∠BCA is x .
In ∆ABC,
∠BAC = 63°
∠ABC = 90° (Angle in a semi-circle is 90°)
∠BCA = x
By using the angle sum property of a triangle, we get
∠BAC + ∠ABC + ∠BCA = 180°
By putting the respected values, we get
63° + 90° + x = 180°
or, 123° + x = 180°
By transposition method, we get
or, x = 180° - 123°
or, x = 57°