Math, asked by huziafamd2, 2 months ago

in each of the following figure, O is the centre of the circle find the values of x and y​

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Answers

Answered by kevilvora07
1

Step-by-step explanation:

Consider the following question.

Using a Pythagoras theorem.

(i)AO=30cm

AB=16cm

AB=BC=y=16cm

x=BO=

(AO)

2

+(AB)

2

=

(30)

2

+(16)

2

=34cm

y=16cm

(ii)AB=12cm

BC=5cm

CA=

(AB)

2

+(BC)

2

=

(12)

2

+(5)

2

=13cm

y=

2

x

=6.5cm

(iii)AB=24cm

AO=x

OB=18cm

AO=x=

(AB)

2

+(OB)

2

=

(24)

2

+(18)

2

x=30cm

y=24cm

Answered by mushahid1234
0

Answer:

X = 13, Y = 12

Step-by-step explanation:

Let 12 cm tangent be touching the circle at T

and y cm tangent be touching it at T'

we know that two tangents drawn on a circle from a same

external point p are equal

Hence length of tangents is equal

i.e. Y = 12

Now in triangle OT'P

OP is perpendicular to T'P

because tangent on a point of a circle is perpendicular to the radius on that point

we can use phythagoras theorem to find OP or x

which is given by

OP² = OT'² + T'P²

X² = 5² + 12²

X² = 25 + 144

X² = 169

X = √169

X = 13

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