In each of the following figures O is the centre of the circle find the value of x and y
Answers
1) here measurement of angle formed at center of circle is is 180 deg
so measurement of angle touching circumference will be 90 deg
now it is a right angle triangle with x as hypoteneus
so
x^2 = (15)^2 + (8)^2
x^2 = 225+64
x^2 = 289
x = 17 cm answer
and x is also diameter
y = radius
so y = x/2 = 17/2 = 8.5 cm answer
2) now according a theorem
• tangents of a circle are perpendicular to its radius
so x is hypoteneus
and base = 5cm (radius)
perpendicular = 12 cm (tangent)
so x^2 = (12)^2 + (5)^2
x^2 = 144 + 25
x^2 = 169
x = 13 cm answer
now here
hypotaneus = x = 13 cm
base = 5cm
perpendicular = y cm
so
(13)^2 = (y)^2 + (5)^2
169 -25 = (y)^2
144 = (y)^2
y = 12 cm answer
which proves that tangents from a common point are equal
3) now if radius (perpendicular) = 24cm
and tangent 1 (base) = 18 cm
and hypoteneus = x cm
so
x^2 = (24)^2 + (18) ^2
x^2 = 576 + 324
x^2 = 900
x = 30 cm answer
now y will be equal to T1 (proved in question 2)
so y = 18 cm answer