Question

In each of the following figures, O is the centre of the circle. Find the values of x and y.




Unnecessary answer will be reported. ​

Answer 1

Step-by-step explanation:

Consider the following question.

Using a Pythagoras theorem.

(i)AO=30cm

AB=16cm

AB=BC=y=16cm

x=BO=

(AO)

2

+(AB)

2

=

(30)

2

+(16)

2

=34cm

y=16cm

(ii)AB=12cm

BC=5cm

CA=

(AB)

2

+(BC)

2

=

(12)

2

+(5)

2

=13cm

y=

2

x

=6.5cm

(iii)AB=24cm

AO=x

OB=18cm

AO=x=

(AB)

2

+(OB)

2

=

(24)

2

+(18)

2

x=30cm

y=24cm

Hence, this is the required answer.

Answer 2

Step-by-step explanation:

(Hypotenuse )² = (Base)² + (perpendicular)²

(Hypotenuse)²= (8)² + (15)²

(Hypotenuse )²= 64 + 225

(Hypotenuse)² = 289

Hypotenuse = √ 289

Hypotenuse = 17

Here the hypotenuse is the diameter of the circle

i.e X = 17

Y = 17/2

Y = 8.5