in each of the following figures one side of a triangle has been produced .find all the angles of the triangle in each case.
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in the given triangle abc angle ACB is equal to 180 - 125 which is equal to 55 angle abc is equal to 180- 50 + 55 =75
thakurdurgeshsingh:
pura solve kro
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as we know that ...
angle A + angle B = angle BCD ( exterior angle sum property )
50° + x = 125°
x = 125° - 50°
x = 75°
then , by angle sum property
angle A + angle B + angle C = 180 °
50° + 75° + angle C = 180°
angle C = 180° - 125°
angle C = 55°
hope this will help uh ....
nd plzz mark as brainliest ....
angle A + angle B = angle BCD ( exterior angle sum property )
50° + x = 125°
x = 125° - 50°
x = 75°
then , by angle sum property
angle A + angle B + angle C = 180 °
50° + 75° + angle C = 180°
angle C = 180° - 125°
angle C = 55°
hope this will help uh ....
nd plzz mark as brainliest ....
Thankyou so much
Please 13 no. ka pura solve Kar dona
hi soumya
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