Question

In each of the following find the value of k, for which the points are collinear.
(2,3),(4,k),(6,-3)

Answer 1

Answer:

k = 0

Step-by-step explanation:

If points are collinear,

Area of triangle formed = 0

Area = 1/2 ( x1 (y2-y3) + x2 (y3-y1) + x3 (y1-y2) )

Hence,

0 = 1/2 ( 2(k+3) + 4(-3-3) + 6(3-k) )

• 0 = 2k + 6 - 24 + 18 -6k
• 0 = -4k +18 -18
• 0 = -4k
• k = 0

Answer 2

Answer:

,

Step-by-step explanation:

1. by section formula m:n=2:2
2. k=0