in each of the following find the value of k for which the points are collinear (7 - 2) (5,1)(3,k)
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Answer:
K=4
Step-by-step explanation:
1/2[7(1-k) + 5(k+2) + 3(-2-1)]=0
7-7k +5k + 10 -6 -3 =0
-2k +8 = 0
-2k = -8
k= 4 ( required ans)
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