Math, asked by prachipaul143, 6 hours ago

In each of the following,show that a-b≠but :
a= -6/15, b= 10/25​

Answers

Answered by Anonymous
1

Answer:

Determine whether the values given against each of the quadratic equation are ... When m=22(2)2-5(2)=0⇒8-10=0⇒-2≠0 ... So, the discriminant b2-4ac=(-5)2-4×2×10=25-80=-55 ... □ABCD is a trapezium AB || CD and its area is 33 cm2 .

Missing: show ‎| Must include: show

Answered by aadesahaja06
0

Solution:

a-b≠(-6/15)-(10/25)

≠{[(-6/15)×45] - [(10/25)×45]} /45

≠{(-6×3)-([10×9]/5)} /45

≠{(-18)-(90)}/45×5

≠{(-18)-(18)} /45

a-b ≠ -36/45

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