Question

in each of the following ,use remainder theorm to find the remainder when f(x) is divided by g(x) f(x)= x³-6x²+2x-4;g(x)=1-3x

Answer 1

g(x) =1-3x =0
3x = -1
x=-1/-3
x=1/3


f(x)= ( x.x.x ) - 6x + 2x -4
$\frac{1}{27} - 2 \times \frac{1}{3} + 2 \times \frac{1}{3} - 4$
$\frac{1}{27} - 2 + \frac{2}{3} - 4$
$\frac{1}{27} + \frac{2}{3} - 6$
$\frac{1 + 6 - 6}{27}$
$\frac{1}{27}$