Question

In each of the following, using remainder theorem, find the remainder when p(x) is divided by 9(x) and verify the result by actual division: (i) p(x) = x2 - 6x2 + 11x - 6, q(x) = x + 2​

Answer 1

$p(x) = x {2} - {6x}^{2} + 11x - 6$

remainder theorem says that if p(x) is divided by x-a then.p (a) is remainders

so, here q(x) = x+2 = 0

x= (-2)

thus, remainder will be P(-2)

x2-6x2 + 11x -6

(-2)2 - 6(-2)2+ 11(-2) -6

4 - 24 - 22-6

- 42.

Answer 2

Answer:

p(x)=x2−6x2+11x−6

remainder theorem says that if p(x) is divided by x-a then.p (a) is remainders

so, here q(x) = x+2 = 0

x= (-2)

thus, remainder will be P(-2)

x2-6x2 + 11x -6

(-2)2 - 6(-2)2+ 11(-2) -6

4 - 24 - 22-6

- 42.