Math, asked by gethtamilan, 15 days ago

In each room the same number of participants are to be seated and all of them being in the

same subject, hence maximum number participants that can accommodated in each room are
a) 14

b) 12

c) 16

d) 18​

Answers

Answered by iamsabharish
31

Step-by-step explanation:

60)84(1

     60

      24)60(2

             48

              12)24(2

                    24

                     0

12)108(9

     108

        0

No: of participants=12

Please mark me as brainliest

Sabharish G

Answered by AnkitaSahni
6

Although your question seems incomplete, you may be referring to the following:

A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English, and Mathematics is 60, 84, and 108 respectively.

1. In each room the same number of participants are to be seated and all of them being in the same subject, hence the maximum number of participants can be accommodated in each room are:

a) 14

b) 12

c) 16

d) 18

Given:

Number of participants in Hindi = 60

Number of participants in English = 84

Number of participants in Mathematics = 108

To Find:

The maximum number of participants can be accommodated in each room if an equal number of participants from each subject is seated.

Solution:

  • The maximum number of students from each subject can be calculated by finding the highest number by which 60, 84, and 108 can be divided with no remainder.
  • Thus, we need to find the Highest Common Factor(HCF) of 60, 84, and 108.

How to find HCF?

1. List out all the factors of each number.

60 = 2 × 2 × 3 × 5

84 = 2 × 2 × 3 × 7

108 = 2 × 2 × 3 × 3 × 3

2. Find common factors between 60, 84, and 108.

  • When we observe the factors of all three numbers we find

                        2 × 2 × 3 = 12

Therefore, 12 is the HCF.

This implies that 12 students of each subject can be seated in each room.

Therefore, the maximum number of students that can be accommodated in each room is option b) 12.

Similar questions