Question

in each side of isoscles tranigle 3√2cm and base is 8 cm then find the area of isoscles traingle ​

Answer 1

Given:

• Each side of an isosceles triangle is 3√2 cm. And, Base of the isosceles triangle is 8 cm.

To find:

• Area of the isosceles triangle.

Solution: ABC is an isosceles triangle and we will know that two sides of isosceles triangle are equal. Therefore, AB is 3√2 cm and AC is 3√2 cm and Base (BC) is 8 cm respectively.

From $\triangle$ ADB,

★ By using Pythagoras theorem ★

$\implies$ (AB)² = (BD)² + (AD)²

$\implies$ (3√2)² = (4)² + (AD)²

$\implies$ 18 = 16 + AD²

$\implies$ AD² = 18 - 16

$\implies$ AD² = 2

$\implies$ AD = √2 ★

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★ FINDING AREA :

★ Area of triangle = 1/2 $\times$ (Base) $\times$ (Height) ★

➠ Area of $\triangle$ = 1/2 $\times$ (BC) $\times$ (AD)

➠ Area of $\triangle$ = 1/2 $\times$ (8) $\times$ (√2)

➠ Area of $\triangle$ = 4√2 cm ★

•°• Hence, area of isosceles triangle is 4√2 cm.

Answer 2

>area of isosceles triangle is 4√2 cm²

⚽ Correct Question ⚽ $\:$

In each side of isoscles tranigle 3√2cm and base is 8 cm then find the area of isoscles traingle

⚽ Step by step explanation ⚽

Given:

Each side of an isosceles triangle is 3√3 cm.

Base of the isosceles triangle is 8 cm.

To find:

Area of the isosceles triangle.

Formula:

Pythagoras theorem:

(AB)² = (BD)² + (AD)²

Solution:

ABC is an isosceles triangle and we will know that two sides of isosceles triangle are equal. Therefore, AB is 3√2 cm and AC is 3√2 cm and Base (BC) is 8 cm respectively.

From ADB,

By using Pythagoras theorem

(AB)² = (BD)² + (AD)²

(3√2)² = (4)² + (AD)²

18 = 16 + AD²

AD² = 18 - 16

AD² = 2

AD = √2

Area of triangle = 1/2 (Base) (Height)

➠ 1/2 (BC) (AD)

➠ 1/2 (8) (√2)

➠ 4√2 cm

•°• Hence,

area of isosceles triangle is 4√2 cm².

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⚽ Know more :-

• Area of right angle triangle = 1/2 * base * height

• Area of rectangle = L x B

• Area of Square = Side x side