Question

. In Edison cell, the anode and cathodes are
respectively Fe and Ni O. The reaction at positive
electrode will be


(1) Fe + 2OH-
FeO + H2O
(2) Ni202 + H2O → Ni
(3) Fe + 20H → Fe₂O₃ + H₂O
(4) Ni,O3 + H20 - 2NiO3 + 20H-​

Answer 1

Answer:

option 3 is correct......