In∆EFG,l(EG)=6cm,m angle F= 65°,m angle G=45°
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In ∆EFG, m∠E + m∠F + m∠G = 180° …(sum of measures of angles of a triangle) m∠E + 65° + 45° = 180° m∠E + 110° = 180° m∠E = 180° – 110° m∠E = 70° Read more on Sarthaks.com - https://www.sarthaks.com/859479/in-efg-l-eg-6-cm-mf-65-mg-45
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