Math, asked by lauraetta, 8 months ago

In ΔEFG, \text{m}\angle E = (8x-16)^{\circ}m∠E=(8x−16)

, \text{m}\angle F = (x+8)^{\circ}m∠F=(x+8)

, and \text{m}\angle G = (2x-10)^{\circ}m∠G=(2x−10)

. What is the value of x?x?

Answers

Answered by antarikshg59
4

Answer:

hey  the value of x in this question is

-11

Step-by-step explanation:

Answered by Dhruv4886
0

The value of 'x' is 18°  

Given:

In ΔEFG, ∠E = (8x-16)°,  m∠F = (x+8)° and  ∠G = (2x-10)°  

To find:

What is the value of x

Solution:  

Complete Question:

In ΔEFG, ∠E = (8x-16)°,  m∠F = (x+8)° and  ∠G = (2x-10)°. What is the value of x?

Condition used:

The sum of angles in a triangle = 180°  

From the data,

The measure of the three angles are

Measure of ∠E = (8x-16)°  

Measure of ∠F = (x+8)°  

Measure of ∠G = (2x-10)°    

Using the above condition

=> m ∠E + m∠F + m ∠G = 180°

=> (8x - 16)° + (x + 8)° + (2x - 10)° = 180°  

=> 11x - 18° = 180°  

=> 11x = 198

=> x = 198/11

=> x = 18°  

Therefore,

The value of 'x' is 18°

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