Question

in equation 2H2S+3O2= 2H2O+2SO2 , reactant side oxygen atoms is 6 but in product side Oxygen atom is 2,4 so how it's balanced equation?​

Answer 1

$2H_{2}S + 3O_{2} \rightarrow 2H_{2}O+2SO_{2}$

Here you can see that 3 × 2 = 6 atoms of oxygen on reactant side.

On the product side :

• 2 oxygen atom from water
• 2 × 2 = 4 oxygen atom from SO2

So, total = 2 + 4 = 6 atoms on product side.