Question

in equation t (2-2t)+6=12 then the value of t​

Answer 1

Answer:

2t-2t²+6=12

-2t²+2t=12-6

-2t²+2t=6

-2t²+2t-6=0

2t²-2t+6=0

there will be no value of t because the roots are imaginary and D(discriminant)<0 hence.....

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