In equilateral Δ ABC, AD is drwan perpendicular to BC and BC = x cm. Find, in terms of x, the length of AD.
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Answer:
Step-by-step explanation:
in triangle abc... all the sides are x cm (equaletral triangle)
in triangle adc
dc =x/2 and ac = x
by Pythagoras theorem
ac^2 = (x/2)^2 + ad^2
x^2-x^2 /4=ad^2
3x^2/4=AD^2
Answered by
0
Answer:
If AD is perpendicular to BC, then AD is a median of Triangle ABC.
As we know that median divides the triangle in two halves.
ATQ,
BC= xcm(given)
In Triangle ABC (equilateral triangle)
AB=BC=AC= xcm
AB+BC+AC=180
x+x+x=180
3x=180
x=180/3
x=60 cm
From above statement, we can write
AD=BC/2
AD=x/2
AD=60/2
AD=30 cm
Hence, the value of AD is 30cm.
HOPE IT HELPS (n_n)
Step-by-step explanation:
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