Question

In equilateral Δ ABC, AD is drwan perpendicular to BC and BC = x cm. Find, in terms of x, the length of AD.​

Answer 1

Answer:

Step-by-step explanation:

in triangle abc... all the sides are x cm (equaletral triangle)

in triangle adc

dc =x/2 and ac = x

by Pythagoras theorem

ac^2 = (x/2)^2 + ad^2

x^2-x^2 /4=ad^2

3x^2/4=AD^2

Answer 2

Answer:

If AD is perpendicular to BC, then AD is a median of Triangle ABC.

As we know that median divides the triangle in two halves.

ATQ,

BC= xcm(given)

In Triangle ABC (equilateral triangle)

AB=BC=AC= xcm

AB+BC+AC=180

x+x+x=180

3x=180

x=180/3

x=60 cm

From above statement, we can write

AD=BC/2

AD=x/2

AD=60/2

AD=30 cm

Hence, the value of AD is 30cm.

HOPE IT HELPS (n_n)

Step-by-step explanation: