in equilateral triangle ABC, AD perpendicular to bc bc=x. find in terms of X the length of AD
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AD<X
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in triangle abc... all the sides are x cm (equaletral triangle)
in triangle adc
dc =x/2 and ac = x
by Pythagoras theorem
ac^2 = (x/2)^2 + ad^2
x^2-x^2 /4=ad^2
3x^2/4=AD^2
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