Question

In equilibrium of 2502 +02 = 2803, equilibrium concentration of SO2, O2 and SO, are 0.3,
0.2 and 0.5 moles/lit respectively then equilibrium constant =​

Answer 1

Answer:

Initially, number of moles of  SO2,O2andSO3 are 2, 1.5 and 0 respectively.

Initially, number of moles of  SO2,O2andSO3 are 2, 1.5 and 0 respectively.2 moles of KMnO4 reacts with 5 moles of SO2.

Initially, number of moles of  SO2,O2andSO3 are 2, 1.5 and 0 respectively.2 moles of KMnO4 reacts with 5 moles of SO2.0.4 moles of KMnO4 will react with 1 moles of SO2.

Initially, number of moles of  SO2,O2andSO3 are 2, 1.5 and 0 respectively.2 moles of KMnO4 reacts with 5 moles of SO2.0.4 moles of KMnO4 will react with 1 moles of SO2.Thus at equilibrium number of moles of  SO2,O2andSO3 are 1, 1 and 1 respectively.

Initially, number of moles of  SO2,O2andSO3 are 2, 1.5 and 0 respectively.2 moles of KMnO4 reacts with 5 moles of SO2.0.4 moles of KMnO4 will react with 1 moles of SO2.Thus at equilibrium number of moles of  SO2,O2andSO3 are 1, 1 and 1 respectively.The volume is 5 L.

Initially, number of moles of  SO2,O2andSO3 are 2, 1.5 and 0 respectively.2 moles of KMnO4 reacts with 5 moles of SO2.0.4 moles of KMnO4 will react with 1 moles of SO2.Thus at equilibrium number of moles of  SO2,O2andSO3 are 1, 1 and 1 respectively.The volume is 5 L.Thus the equilibrium concentrations of  SO2,O2andSO3 are 0.2, 0.2 and 0.2 respectively.

Initially, number of moles of  SO2,O2andSO3 are 2, 1.5 and 0 respectively.2 moles of KMnO4 reacts with 5 moles of SO2.0.4 moles of KMnO4 will react with 1 moles of SO2.Thus at equilibrium number of moles of  SO2,O2andSO3 are 1, 1 and 1 respectively.The volume is 5 L.Thus the equilibrium concentrations of  SO2,O2andSO3 are 0.2, 0.2 and 0.2 respectively.The expression for the equilibrium constant is Kp[SO2]2[O2][SO3]2=0.22×0.20.22=5.