Math, asked by Rohanchetri, 4 months ago

in examination 43% paseed in math 48% passed in physics and 52% passed in chemistry only 8% paseed a n all maths and physics 21% passed in maths and chemistry Number of students who took the exam is 200 then how many students passed in maths only​

Answers

Answered by amitnrw
4

Given :

In an examination 43% pas sed in Math, 52% passed in Physics and 52% passed in Chemistry.

Only 8% students pas sed in all the three. 14% passed in Math and

Physics and 21% pas sed in Math and Chemistry and 20% pas sed in Physics and Chemistry. Number of students who took the exam is 200

To Find : how many students pas sed in maths only​

Solution:

Pas sed in Maths M  = 43 %

Pas sed in Math and Physics M ∩ P  = 14  %

Pas sed in Math and Chemistry M ∩ C  = 21  %

Pas sed in All M ∩ P ∩ C  = 8  %

Pas sed in maths only​  = M - M ∩ P - M ∩ C + M ∩ P ∩ C

= 43 - 14 - 21  + 8

= 16 %

students pas sed in maths only​ = (16/100)200 = 32

32 students pas sed in maths only

learn More:

Venn diagram  Which of the option(s) is (are) correct?

brainly.in/question/21812746

Venn diagram Which of the option(s) is (are) correct?

brainly.in/question/22299846

Answered by byemail007
0

Answer:

Step-by-step explanation:

We can solve this problem using the Principle of Inclusion-Exclusion. According to this principle, for three sets A (Maths), B (Physics), and C (Chemistry), the percentage of people who passed at least one subject can be calculated as:

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

Given the information from the problem, we have:

P(A) = 43%

P(B) = 48%

P(C) = 52%

P(A ∩ B) = 14%

P(A ∩ C) = 21%

P(B ∩ C) = 20%

P(A ∩ B ∩ C) = 8%

Now, calculate P(A ∪ B ∪ C):

P(A ∪ B ∪ C) = 43% + 48% + 52% - 14% - 21% - 20% + 8%

P(A ∪ B ∪ C) = 96%

Since there are 200 students who took the exam, the number of students who passed at least one subject is:

Number of students = 200 * 96% = 192

Next, we want to find the number of students who passed in Maths only. We can use the formula:

P(A only) = P(A) - P(A ∩ B) - P(A ∩ C) + P(A ∩ B ∩ C)

P(A only) = 43% - 14% - 21% + 8%

P(A only) = 16%

Now, we can find the number of students who passed in Maths only:

Number of students = 200 * 16% = 32

So, the answer is: 32

Similar questions