Question

In examination,no. of students in Hindi, English and math are 60,84,108respectively.find minimum number of rooms required,if in each room same number of students are to be seated and all of them being of same subject.

Answer 1

answer1///Sol: Number of participants in each room = HCF of 36, 60, 84 36 = 2 x 2 x 3 x 3 60 = 2 x 2 x 3 x 5 84 = 2 x 2 x 3 x 7 HCF = 2 x 2 x 3 = 12 So, the number of students in each class = 12 Total number of students = 36 + 60+ 84 = 180 Number of rooms required = 180 / 12 = 15.



answer2////
the number of participants in each room must be the HCF of 60, 84 and 108.

so by euclid's division lemma,

108= 84*1+24

84= 24*3+12

24=12*2

therefore, the hcf of 108 and 84 is 12.

similarly the hcf of 60 and 84 will be 12.

 

therefore in each room, 12 members can sit.

total number of participants= 60+84+108=252

munber of rooms required= total students/number of students in one room

                                               = 252/12=21

therefore 21 rooms are required

this your answer I hope this will help you

Answer 2

Answer:

Number of rooms=21

Step-by-step explanation:

Given : In a examination, number of student in Hindi English and mathematics are 60, 84, 108 respectively.

To find : The number of rooms required, if in each room the same number of student are to be seated and all of them being the same subject?

Solution :

The number of students seated in each room would be H.C.F of all the three values above.

HCF is the highest common factor,

60 =2×2×3×5

84=2×2×3×7

108=2×2×3×3×3

HCF(60,84,108)= 2×2×3=12

Now no. of rooms required are total number of students divided by no. of students in each room.

Number of rooms=(60+84+108)/12

Number of rooms=21