Question

In examination the grades are awarded to the students in science according to the average marks obtained in the examination :
Marks Grades

80% and above Distinction

60% or more but less than 80% First Division

45% or more but less than 60% Second Division

40% or more but less than 45% Pass

less then 40% Promotion not granted


Write a program to input name and marks in physics, chemistry and biology .Calculate the average marks. Display the name, average marks and the grade obtained.

Answer 1

Answer:

#include<iostream.h>

using namespace std;

int main()

{

int rollno[],biology[], physics[], chemistry[],sum[], avg[],n;char name[];

cout<<"Enter no of Students";

cin>>n;

for(int i=0;i<n;i++)

{

cout<<"Enter rollno:\n";

cin>>rollno[i];

cout<<"Enter name of student:\n"

gets(name [i]);

cout<<"Enter marks of Biology";

cin>>biology [i];

cout<<"Enter marks of chemistry";

cin>>chemistry[i];

cout<<"Enter marks of physics";

cin>>physics;

sum[i]=physics [i]+chemistry [i]+physics [i];

avg[i]=sum[i]/3;

}

for(int i=0;i<n;i++)

{

cout<<"roll no:"<<rollno[i]<<"Name:"<<name[i]<<"Average marks:"<<avg[i]<<"Grade obtained";

if(avg[i]>=80)

cout<<"Distinction";

elseif(avg[i]<80&&avg[i]>=60)

cout<<"first division";

elseif(avg[i]<60&&avg[i]>=45)

cout<<"Second division";

elseif(avg[i]<45&&avg[i]>=40)

couy<<"pass";

else

cout<<" promotion not granted";

}

Explanation:

please complie the program once and if any error occurs u can contact me...

This program can be made by many methods i.e functions,classes,structures...