in family of three children find the probability of having at least one boy
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The probability that each child will be a boy is 1/2.
The probability that each child will be a girl is 1/2. The probability of no. boys = 1/2 × 1/2 × 1/2 = 1/8 The probability of at least 1 boy = 1 - the probability of no boys. = 1 - 1/8 = 7/8 or The number of the possibilities is shown below Probability of 0 boys = 1/8
Probability of 1 boy = 3 × 1/8 = 3/8
Probability of 2 boys = 3 × 1/8 = 3/8
Probability of 3 boys = 1/8
The probability of at least 1 boy is equal to the probability of 1 or 2 or 3 boys which = 3/8 + 3/8 + 1/8 = 7/8.
The probability that each child will be a girl is 1/2. The probability of no. boys = 1/2 × 1/2 × 1/2 = 1/8 The probability of at least 1 boy = 1 - the probability of no boys. = 1 - 1/8 = 7/8 or The number of the possibilities is shown below Probability of 0 boys = 1/8
Probability of 1 boy = 3 × 1/8 = 3/8
Probability of 2 boys = 3 × 1/8 = 3/8
Probability of 3 boys = 1/8
The probability of at least 1 boy is equal to the probability of 1 or 2 or 3 boys which = 3/8 + 3/8 + 1/8 = 7/8.
sakshiraval:
but the answer is 7/8 . I don't understand it plz right answwr
which book is question from
navneet activity sheet
the answer can be wrong confirm it with your teacher
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no. of children =3
no. of boy= 1
probability =1/3
no. of boy= 1
probability =1/3
but answer is 7/8 I don't understand it
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