In fcc packing, tetrahedral voids divide a body diagonal in the ratio of
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tetrahedral void are present at centre of body diagonal and at the body diagonal two tetrahedral void are present so it divide the diagonal in 1:2:1
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can you explain to me more clearly
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Tetrahedral voids are present at a distance of 1/4th of the body diagonal from either vertex. Hence, the body diagonal is divided into 1:2:1.
The image will help understand better.
The image will help understand better.
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