Question

in Fe4[Fe(CN)613, average oxidation number of iron in Feq[Fe(CN)6]z is 'a'
, oxidation number of central iron atom is brande
is 'c'. So a, b, care respectively
+5/2, +3, +2
+18/7, +3, +2
+18/7, +2, +3
+5/2, +2, +3
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Answer 1

Answer:

Each [Fe(Fe(CN)6)] is then a −1 , so with each [Fe(CN)6]4− being a 4− charge, the bolded iron is a +3 .

Explanation:

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