in fig 1.1 LPOR and LQOR form a linear pair . of a-b =80 find a and b.
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HEY THERE ..!!
HERE IS YOURS SOLUTION;
◆ Given:
● ∠POR & ∠QOR forms linear pair.
● ∠a - ∠b = 80°
◆ To Find:
● ∠a & ∠b
◆ Solution:
We know that;
∠a + ∠b = 180° 【Linear pair angles】
=> ∠a = 180° - ∠b -------1)
Now, we have given that;
∠a - ∠b = 80°
So, we put value of ∠a in this;
180° - ∠b - ∠b = 80°
=> 180° - 2∠b = 80°
=> -2∠b = -100°
=> 2∠b = 100°
=> ∠b = 50°
Now, we put the value of ∠b in eq" 1) ;
∠a = 180° - ∠b
=> ∠a = 180° - 50°
=> ∠a = 130°
★So, ∠a = 130° & ∠b = 50°★
↓FOR ANY DOUBTS JUST COMMENT DOWN↓
HOPE IT HELPS
HERE IS YOURS SOLUTION;
◆ Given:
● ∠POR & ∠QOR forms linear pair.
● ∠a - ∠b = 80°
◆ To Find:
● ∠a & ∠b
◆ Solution:
We know that;
∠a + ∠b = 180° 【Linear pair angles】
=> ∠a = 180° - ∠b -------1)
Now, we have given that;
∠a - ∠b = 80°
So, we put value of ∠a in this;
180° - ∠b - ∠b = 80°
=> 180° - 2∠b = 80°
=> -2∠b = -100°
=> 2∠b = 100°
=> ∠b = 50°
Now, we put the value of ∠b in eq" 1) ;
∠a = 180° - ∠b
=> ∠a = 180° - 50°
=> ∠a = 130°
★So, ∠a = 130° & ∠b = 50°★
↓FOR ANY DOUBTS JUST COMMENT DOWN↓
HOPE IT HELPS
DonDj:
Thank You
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