Question

in fig 1.2 AD=BC and AD||to BC prove ab=dc

Answer 1

Answer:

in triangle ADC and triangle ABC,

BC=AD(given)

angle BCA = angle CAD ( alternate interior angles as AD||BC and AC is trans.)

AC=AC(Common)

therefore, triangle ADC = triangle ABC(SAS)

Therefore AB=DC (C.P.C.T.C)

Hence proved

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