In fig 1.2 , two straight line pq and rs intersect at o .if pot = 75. find the value of a , b,c.
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take RS line ,
4b+75+b = 180
5b = 180-75=105
b= 105/5 = 21
now take PQ line,
75+b+a =180
75+21+a =180
a = 180-75-21 =84
now again take RS line for uper angle
2c+a = 180
2c = 180-84=96
c = 48
hence,
a=84
b=21
c=48
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