Question

in fig 1 AB=CF,EF=BDand angleAFE=CBD prove that triangleAEF=CBD

Answer 1

Bonjour ❤️

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✔️GIVEN :–

AB = CF

EF = BD

angle AFE = CBD

✔️TO PROVE :–

∆AEF (congruent) ∆CBD

✔️ PROOF :–

In ∆ AEF and ∆ CBD

AB = CF .........................( given )

AB + BF = CF + FB

=> AF = CB ....................( BF is added to equals )

EF = BD ..........................( given )

angle AFE = CBD ........( given )

✔️HENCE,

∆ AEF (congruent) ∆ CBD ........( S.A.S. ) proved

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hope it will help you ✌️✌️

Answer 2

Here you go!!

 $\huge\underline \mathfrak \red{Solution}$

We have, AB = CF

=> AB + BF = CF + BF

=> AF = CB ....... [1]

In ∆sAFE and CBD, we have

AF = CB ........[From 1]

∠AFE = ∠DBC ........ [Given]

and, EF = BD .......... [Given]

Therefore, by SAS criterion of congruence, we have

∆AFE = ∆CBD