Math, asked by jiyayadav776, 9 months ago

In fig.1 angle A and angle B form a linear pair , if a-b=100° then angle A and angle B are?​

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Answered by Anonymous
4

\bigstar Question:

  • In this figure, \angle a and \angle b are forming a linear pair. If \angle a - \angle b = 100°, find the Values of \angle a and \angle b.

\bigstarTo Find:

  • The values of \angle a and \angle b.

\bigstar Solution:

\because \angle a + \angle b are forming a linear pair,

\therefore \angle a + \angle b = 180° .....( i )

Now, \angle a - \angle b = 100°

( Given ) ......( ii )

Now, let's subtract equation (ii) from (i),

\therefore \angle a + \angle b - \angle a + \angle b = 180° - 100°

( using - (a - b) = (-a) + b )

\implies 2\angle b = 80°

\implies \angle b = 40°

\therefore \angle b = 40°

Now, by substituting the value of \angle b in equation (i) we get,

\rightarrow\angle a + \angle b = 180°

\implies\angle a + 40° = 180°

\implies \angle a = 180° - 40°

\implies\angle a = 140°

\therefore \angle a = 140°

\bigstarAnswer:

[tex]\therefore[/tex] \angle a = 140° and \angle b = 40°

Answered by Anonymous
3

Correct Question :-

  • ∠ A and ∠ B are forming in a linear pair , if a - b = 100° then ∠A and ∠B are ?

Solution :-

∠A - ∠B = 100

∠A = 100 + ∠B -------(i)

And,

∠A + ∠B = 180°

Put the value of ∠A from equation (i) →

100 + ∠B + ∠B = 180

100 + 2(∠B) = 180

2(∠B) = 180 - 100

2(∠B) = 80

∠B = 80/2

∠B = 40°

Now, put the value of B into equation (i)

∠A = 100 + ∠B

∠A = 100 + 40

A = 140

Hence, The angles A and B are 140° and 40°

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